C++ | Function Overloading

Question: 8
C++ program to calculate and print product of 2 numbers, the number may be an integer, float, or double.
Sol:

#include<iostream>
using namespace std;
int prod(int n1,int n2)
{
	return(n1*n2);
}
float prod(float n1,float n2)
{
	return(n1*n2);
}
double prod(double n1,double n2)
{
	return(n1*n2);
}
int main()
{
	int a1,a2,a3;
	float b1,b2,b3;
	double d1,d2,d3;
	//int
	cout<<"Enter 2 nos (int) ";
	cin>>a1>>a2;
	a3=prod(a1,a2);
	cout<<"prod = "<<a3<<endl;
	//float
	cout<<"Enter 2 nos (float) ";
	cin>>b1>>b2;
	b3=prod(b1,b2);
	cout<<"prod = "<<b3<<endl;
	//double
	cout<<"Enter 2 no2 (double) ";
	cin>>d1>>d2;
	d3=prod(d1,d2);
	cout<<"prod = "<<d3<<endl;
	return(0);
}

/* Output */
Enter 2 nos (int) 2
3
prod = 6
Enter 2 nos (float) 3.2
6.32
prod = 20.224
Enter 2 no2 (double) 23.36
5632.325
prod = 131571

Question:9
C++ program to calculate and print average of 2 numbers, the number may be an integer, float, or double.
Sol:

#include<iostream>
using namespace std;
int avg(int n1,int n2)
{
     return((n1+n2)/2);
}
float avg(float n1,float n2)
{
     return((n1+n2)/2);
}
double avg(double n1,double n2)
{
     return((n1+n2)/2);
}
int main()
{
     int a1,a2,a3;
     float b1,b2,b3;
     double d1,d2,d3;
     //int
     cout<<"Enter 2 nos (int) ";
     cin>>a1>>a2;
     a3=avg(a1,a2);
     cout<<"avg = "<<a3<<endl;
     //float
     cout<<"Enter 2 nos (float) ";
     cin>>b1>>b2;
     b3=avg(b1,b2);
     cout<<"avg = "<<b3<<endl;
     //double
     cout<<"Enter 2 no2 (double) ";
     cin>>d1>>d2;
     d3=avg(d1,d2);
     cout<<"avg = "<<d3<<endl;
     return(0);
}

/* Output */
Enter 2 nos (int) 10
20
avg = 15
Enter 2 nos (float) 3.2
2.3
avg = 2.75
Enter 2 no2 (double) 236.32
563.325
avg = 399.822