Menu Driven programs
Question:
C++ program to find maximum of 2 and 3 numbers. Minimum of 2 and 3 numbers?
Sol:
#include<iostream>
#include<stdlib.h>
#include<conio.h>
using namespace std;
int max(int n1,int n2)
{
if(n1>n2)
return(n1);
else
return(n2);
}
int max(int n1,int n2,int n3)
{
if(n1>n2 && n1>n3)
return(n1);
else
if(n2>n3)
return(n2);
else
return(n3);
}
int min(int n1,int n2)
{
if(n1<n2)
return(n1);
else
return(n2);
}
int min(int n1,int n2,int n3)
{
if(n1<n2 && n1<n3)
return(n1);
else
if(n2<n3)
return(n2);
else
return(n3);
}
//method:2
int main()
{
int a1,a2,a3,a4,op=0;
while(op!=5)
{
system("cls"); //to clear the screen header file <stdlib.h>
cout<<"1. max of 2 nos"<<endl;
cout<<"2. Max of 3 nos "<<endl;
cout<<"3. Min of 2 nos"<<endl;
cout<<"4. Min of 3 nos "<<endl;
cout<<"5. Exit"<<endl;
cout<<"Enter your choice ";
cin>>op;
switch(op)
{
case 1:
cout<<"Enter 2 nos ";
cin>>a1>>a2;
a4=max(a1,a2);
cout<<"Max of 2 nos "<<a4<<endl;
break;
case 2:
cout<<"Enter 3 nos ";
cin>>a1>>a2>>a3;
a4=max(a1,a2,a3);
cout<<"Max of 3 nos "<<a4<<endl;
break;
case 3:
cout<<"Enter 2 nos ";
cin>>a1>>a2;
a4=min(a1,a2);
cout<<"Min of 2 nos "<<a4<<endl;
break;
case 4:
cout<<"Enter 3 nos ";
cin>>a1>>a2>>a3;
a4=min(a1,a2,a3);
cout<<"Min of 3 nos "<<a4<<endl;
break;
case 5:
cout<<"End"<<endl;
break;
default:
cout<<"Invalid choice"<<endl;
break;
}//switch
getch();
}//while
return(0);
}//main
/* Output */ 1. max of 2 nos 2. Max of 3 nos 3. Min of 2 nos 4. Min of 3 nos 5. Exit Enter your choice 2 Enter 3 nos 25 96 34 Max of 3 nos 96 1. max of 2 nos 2. Max of 3 nos 3. Min of 2 nos 4. Min of 3 nos 5. Exit Enter your choice 4 Enter 3 nos 25 98 45 Min of 3 nos 25
