C Language | Arrays 17

Question:7
C program to take input for a string, display the string in such a manner that all lower case alphabets are displayed as upper case and rest are displayed as it is.
Sol:

/* Using for loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20];
  int i=0;
  printf("Enter any string ");
  gets(n);
  for(i=0;n[i]!='\0';i++)
  {
      if(n[i]>='a' && n[i]<='z')
        printf("%c",n[i]-32);
      else
        printf("%c",n[i]);
  }
   return(0);
}

/* Using while loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20];
  int i=0;
  printf("Enter any string ");
  gets(n);
  while(n[i]!='\0')
  {
      if(n[i]>='a' && n[i]<='z')
        printf("%c",n[i]-32);
      else
        printf("%c",n[i]);
      i++;
  }
   return(0);
}

/* Output */

Enter any string Hello hi
HELLO HI

Question:8
C program to take input for a string, display the string in toggle case (i.e. all upper case alphabets are displayed as lower case, lower case are displayed as upper case and rest are displayed as it is).
ASCII Values
A –Z : 65 – 90
a- z: 97 – 122
0-9 : 48 – 57
Sol:

/* Using for loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20];
  int i=0;
  printf("Enter any string ");
  gets(n);
  for(i=0;n[i]!='\0';i++)
  {
      if(n[i]>='a' && n[i]<='z')
        printf("%c",n[i]-32);
    else
        if(n[i]>='A' && n[i]<='Z')
        printf("%c",n[i]+32);
    else
        printf("%c",n[i]);
  }
   return(0);
}

/* Using while loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20];
  int i=0;
  printf("Enter any string ");
  gets(n);
  while(n[i]!='\0')
  {
      if(n[i]>='a' && n[i]<='z')
        printf("%c",n[i]-32);
    else
        if(n[i]>='A' && n[i]<='Z')
        printf("%c",n[i]+32);
    else
        printf("%c",n[i]);
    i++;
  }
   return(0);
}

/* Output */

Enter any string CoMpUtEr
cOmPuTeR

Question:9
C program to take input for a string, further take input for a character to search, check and print whether the character is present in the string or not? (Searching)
Sol:

/* Using for loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20],ch;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  scanf("%c",&ch);
  for(i=0;n[i]!='\0';i++)
  {
      if(n[i]==ch)
      {
          z=1;
          break;
      }
  }
  if(z==0)
    printf("character is not present");
  else
    printf("character is present");
   return(0);
}

/* Using while loop */
#include<stdio.h>
#include<ctype.h>
int main()
{
  char n[20],ch;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  scanf("%c",&ch);
  while(n[i]!='\0')
  {
      if(n[i]==ch)
      {
          z=1;
          break;
      }
    i++;
  }
  if(z==0)
    printf("character is not present");
  else
    printf("character is present");
   return(0);
}

/* Output */

case:1
Enter any string hello
Enter the character to search k
character is not present

case:2
Enter any string computer
Enter the character to search p
character is present

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