Double Dimension Numeric Array

While declaring a double dimension array we have to specify two dimensions one for number of rows and second for number of columns.

Syntax:
Datatype arrayname[rows][cols];

int a[3][3];
int a[4][5];
int a[2][3];

int A[3][3];

(logical representation of double dimension array)

Initialization of two dimensional array

(i)
int a[3][3]={1,2,3,4,5,6,7,8,9};
(ii)
int a[3][3]={
                     {1,2,3},
                     {4,5,6},
                     {7,8,9}
                 };

Examples:

Question:1.
C program to Take input for the elements of a double dimension array of dimension R X C. Further display the elements in the form of a matrix.
Sol:

#include<stdio.h>

int main()
{
    int a[10][10],r,c,i,j;
    /* clrscr(); */
    printf("Enter total rows and cols ");
    scanf("%d %d",&r,&c);
    for(i=0;i<r;i++)
    {
        for(j=0;j<c;j++)
        {
            printf("Enter [%d][%d] element ",i,j);
            scanf("%d",&a[i][j]);
        }
    }
  for(i=0;i<r;i++)
  {
        for(j=0;j<c;j++)
        {
            printf("%4d",a[i][j]);
        }
        printf("\n");
    }
    return 0;
}

/* Output */

Enter total rows and cols 3
3
Enter [0][0] element 1
Enter [0][1] element 2
Enter [0][2] element 3
Enter [1][0] element 4
Enter [1][1] element 5
Enter [1][2] element 6
Enter [2][0] element 7
Enter [2][1] element 8
Enter [2][2] element 9

   1   2   3
   4   5   6
   7   8   9

Question:2.
C program to Take the input for the elements of a double dimension array of dimension R X C. Further display the elements in the form of a matrix. Also, calculate and print the sum of all the elements.

Example:
1 2 3
4 5 6
7 8 9
Sum = 45

Sol:

#include<stdio.h>

int main()
{
    int a[10][10],r,c,i,j,s=0;
    /* clrscr(); */
    printf("Enter total rows and cols ");
    scanf("%d %d",&r,&c);
    for(i=0;i<r;i++)
    {
        for(j=0;j<c;j++)
        {
            printf("Enter [%d][%d] element ",i,j);
            scanf("%d",&a[i][j]);
        }
    }
  for(i=0;i<r;i++)
  {
        for(j=0;j<c;j++)
        {
            printf("%4d",a[i][j]);
            s=s+a[i][j];
        }
        printf("\n");
    }
    printf("Sum of all the elements = %d\n",s);
    return 0;
}

/* Output */

Enter total rows and cols 3
3
Enter [0][0] element 1
Enter [0][1] element 2
Enter [0][2] element 3
Enter [1][0] element 4
Enter [1][1] element 5
Enter [1][2] element 6
Enter [2][0] element 7
Enter [2][1] element 8
Enter [2][2] element 9
   1   2   3
   4   5   6
   7   8   9
Sum of all the elements = 45