C Language | Arrays 18

Question:10
C program to take input for a string , further take input for a character to search , check and print whether the character is present in the string or not, if present also print how many times it is present?(Search and count)
Sol:

/* Using for loop */
#include<stdio.h>
int main()
{
  char n[20],ch;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  scanf("%c",&ch);
  for(i=0;n[i]!='\0';i++)
  {
      if(n[i]==ch)
      {
          z=z+1;
      }
  }
  if(z==0)
    printf("character is not present");
  else
    printf("character is present %d times",z);
   return(0);
}

/* Using while loop */
#include<stdio.h>
int main()
{
  char n[20],ch;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  scanf("%c",&ch);
  while(n[i]!='\0')
  {
      if(n[i]==ch)
      {
          z=z+1;
      }
    i++;
  }
  if(z==0)
    printf("character is not present");
  else
    printf("character is present %d times",z);
   return(0);
}

/* Output */

case:1

Enter any string hello
Enter the character to search l
character is present 2 times

case:2

Enter any string hello
Enter the character to search k
character is not present

Question:11
C program to take input for a string , further take input for a character to search and input for a character to replace with?(Search and replace)
Example:
n=”hello”
character to search : l
character to replace with : a
output: heaao
Sol:

/* Using for loop */
#include<stdio.h>
int main()
{
  char n[20],ch,ch1;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  fflush(stdin);
  scanf("%c",&ch);
  printf("Enter new character ");
  fflush(stdin);
  scanf("%c",&ch1);
  for(i=0;n[i]!='\0';i++)
  {
      if(n[i]==ch)
      {
          z=1;
          n[i]=ch1;
      }
  }
  if(z==0)
    printf("character is not present");
  else
    printf("After replacement string is %s",n);
   return(0);
}

/* Using while loop */
#include<stdio.h>
int main()
{
  char n[20],ch,ch1;
  int i=0,z=0;
  printf("Enter any string ");
  gets(n);
  printf("Enter the character to search ");
  fflush(stdin);
  scanf("%c",&ch);
  printf("Enter new character ");
  fflush(stdin);
  scanf("%c",&ch1);
  while(n[i]!='\0')
  {
      if(n[i]==ch)
      {
          z=1;
          n[i]=ch1;
      }
    i++;
  }
  if(z==0)
    printf("character is not present");
  else
    printf("After replacement string is %s",n);
   return(0);
}

/* Output */

case:1

Enter any string hello
Enter the character to search k
Enter new character l
character is not present

case:2

Enter any string hello
Enter the character to search l
Enter new character a
After replacement string is heaao

Question:12
C program to take input for a string and copy it into another string ?
example:
n1=”hello”
copied string n2=”hello”
Sol:

#include<stdio.h>
int main()
{
  char n1[20],n2[20];
  int i=0,j=0;
  printf("Enter any string ");
  gets(n1);
  while(n1[i]!='\0')  //for(;n1[i]!='\0';)
  {
    n2[i]=n1[i];
    i++;
  }
  n2[i]='\0';
  printf("copied string is %s\n",n2);
  getch();
  return(0);
}

/* Output */

Enter any string computer
copied string is computer