C Language | Arrays 4

Question:4
C program to take input for 5 elements using an array, check and print total +ve elements in the array.
Sol:

#include<stdio.h>

int main()
{
    int a[5],i,p=0;
    /* input */
    for(i=0;i<5;i++)
    {
        printf("Enter %d element ",i);
        scanf("%d",&a[i]);
    }
    /* display */
    for(i=0;i<5;i++)
    {
        printf("%d\n",a[i]);
        if(a[i]>0)
            p++;
    }
    printf("Total +ve elements =  %d\n",p);

    return(0);
}

/* Output */
Enter 0 element 10
Enter 1 element -96
Enter 2 element 35
Enter 3 element -85
Enter 4 element 78
10
-96
35
-85
78
Total +ve elements =  3

Question:5
C program to take input for 5 elements using an array, check and print total -ve elements in the array.
Sol:

#include<stdio.h>

int main()
{
    int a[5],i,ne=0;
    /* input */
    for(i=0;i<5;i++)
    {
        printf("Enter %d element ",i);
        scanf("%d",&a[i]);
    }
    /* display */
    for(i=0;i<5;i++)
    {
        printf("%d\n",a[i]);
        if(a[i]<0)
            ne++;
    }
    printf("Total -ve elements =  %d\n",ne);

    return(0);
}

/* Output */
Enter 0 element 25
Enter 1 element -6
Enter 2 element 75
Enter 3 element -85
Enter 4 element -74
25
-6
75
-85
-74
Total -ve elements =  3

Question:6
C program to take input for 5 elements using an array, check and print total even elements in the array.
Sol:

#include<stdio.h>

int main()
{
    int a[5],i,e=0;
    /* input */
    for(i=0;i<5;i++)
    {
        printf("Enter %d element ",i);
        scanf("%d",&a[i]);
    }
    /* display */
    for(i=0;i<5;i++)
    {
        printf("%d\n",a[i]);
        if(a[i]%2==0)
            e++;
    }
    printf("Total even elements =  %d\n",e);

    return(0);
}

/* Output */
Enter 0 element 25
Enter 1 element 26
Enter 2 element 35
Enter 3 element 98
Enter 4 element 45
25
26
35
98
45
Total even elements =  2