Solution with out using functions(Using For Loop)

Solution with out using functions(Using While Loop)

Solution using functions without passing arguments

Solution using functions and by passing arguments

Spy Number :

If the Sum of the digits and Product of the digits same then the number is said to be a Spy number.

example:
n=123
Sum of digits=6
Product of digits=6
Number is a Spy number

n=234
Sum of digits=9
Product of digits=24
Number is a not Spy number

 

C program to check number is a spy number or not(Using For Loop)

Solution : Without using function
Program/Source Code

#include <stdio.h>

int main()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    for(;n>0;)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
    return 0;
}

Output:

case 1:

Enter any no 253
Sum of digits = 10 Product of digits = 30
Number is not a Spy Number

case 2:

Enter any no 123
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

C program to check number is a spy number or not(Using While Loop)

Solution : Without using function
Program/Source Code

#include <stdio.h>

int main()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
    return 0;
}

Output:

case 1:

Enter any no 321
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

case 2:

Enter any no 365
Sum of digits = 14 Product of digits = 90
Number is not a Spy Number

C program to check number is a spy number or not

Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
void check()
{
    int n,s=0,p=1,d;
    printf("Enter any no ");
    scanf("%d",&n);
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
}

int main()
{
    check();
    return 0;
}

Output:

case 1:

Enter any no 312
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

case 2:

Enter any no 145
Sum of digits = 10 Product of digits = 20
Number is not a Spy Number

C program to check number is a spy number or not

Solution : Using function Passing Arguments
Program/Source Code

#include <stdio.h>
void check(int n)
{
    int s=0,p=1,d;
    while(n>0)
    {
        d=n%10;
        s=s+d;
        p=p*d;
        n=n/10;
    }
    printf("Sum of digits = %d Product of digits = %d\n",s,p);
    if(s==p)
        printf("Number is a Spy Number");
    else
        printf("Number is not a Spy Number");
}

int main()
{
    int n;
    printf("Enter any no ");
    scanf("%d",&n);

    check(n);
    return 0;
}

Output:

case 1:

Enter any no 965
Sum of digits = 20 Product of digits = 270
Number is not a Spy Number

case 2:

Enter any no 231
Sum of digits = 6 Product of digits = 6
Number is a Spy Number

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