Solution with out using functions
Solution using functions without passing arguments
Solution using functions and by passing arguments
Solution : Without using function
Program/Source Code
#include <stdio.h>
int main()
{
int n;
printf("Enter any no ");
scanf("%d",&n);
if(n%5==0)
printf("Number is multiple of 5");
else
printf("Number is not multiple of 5");
return 0;
}
Output:
case :1
Enter any no 85
Number is multiple of 5
case :2
Enter any no 36
Number is not multiple of 5
Solution : Using function Without Passing Arguments
Program/Source Code
#include <stdio.h>
void check()
{
int n;
printf("Enter any no ");
scanf("%d",&n);
if(n%5==0)
printf("Number is multiple of 5");
else
printf("Number is not multiple of 5");
}
int main()
{
check();
return 0;
}
Output:
case :1
Enter any no 45
Number is multiple of 5
case :2
Enter any no 66
Number is not multiple of 5
Solution : Using function Passing Arguments
Program/Source Code
#include <stdio.h>
void check(int n)
{
if(n%5==0)
printf("Number is multiple of 5");
else
printf("Number is not multiple of 5");
}
int main()
{
int n;
printf("Enter any no ");
scanf("%d",&n);
check(n);
return 0;
}
Output:
case :1
Enter any no 25
Number is multiple of 5
case :2
Enter any no 26
Number is not multiple of 5
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