C program to check number is prime number or not

Solution Without using function(Using for loop)
Solution Without using function(Using while loop)
Solution Using functions with out passing arguments
Solution Using function by passing arguments
Solution Using function by passing arguments and returning value

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C program to check number is prime number or not

Solution : Without using function(Using for loop)
Program/Source Code

#include <stdio.h>

int main()
{
    int n,i,z=0;
    printf("Enter any no ");
    scanf("%d",&n);
    for(i=2;i<n;i++)
    {
        if(n%i==0)
        {
            z=1;
            break;
        }
    }
    if(z==0)
        printf("Number is prime");
    else
        printf("Number is not prime");

    return 0;
}

Output:

case 1:
Enter any no 25
Number is not prime

case 2:
Enter any no 3
Number is prime



C program to check number is prime number or not

Solution : Without using function(Using while loop)
Program/Source Code

#include <stdio.h>

int main()
{
    int n,i,z=0;
    printf("Enter any no ");
    scanf("%d",&n);
    i=2;
    while(i<n)
    {
        if(n%i==0)
        {
            z=1;
            break;
        }
        i++;
    }
    if(z==0)
        printf("Number is prime");
    else
        printf("Number is not prime");

    return 0;
}

Output:

Enter any no 26
Number is not prime

Enter any no 17
Number is prime



C program to check number is prime number or not

Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
/* function definition */
void prime()
{
    int n,i,z=0;
    printf("Enter any no ");
    scanf("%d",&n);
    for(i=2;i<n;i++)
    {
        if(n%i==0)
        {
            z=1;
            break;
        }
    }
    if(z==0)
        printf("Number is prime");
    else
        printf("Number is not prime");

}
int main()
{
    prime(); /* function calling */

    return 0;
}

Output:

case 1:
Enter any no 36
Number is not prime

case 2:
Enter any no 53
Number is prime



C program to check number is prime number or not

Solution : Using function By Passing Arguments
Program/Source Code

#include <stdio.h>
/* function definition */
void prime(int n)
{
    int i,z=0;
    for(i=2;i<n;i++)
    {
        if(n%i==0)
        {
            z=1;
            break;
        }
    }
    if(z==0)
        printf("Number is prime");
    else
        printf("Number is not prime");

}
int main()
{
    int n;
    printf("Enter any no ");
    scanf("%d",&n);
    prime(n); /* function calling */

    return 0;
}

Output:

case 1:
Enter any no 125
Number is not prime

case 2:
Enter any no 197
Number is prime


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