Solution with out using functions(Using For Loop)
Solution with out using functions(Using While Loop)
Solution using functions without passing arguments
Solution using functions and by passing arguments

C program to print all prime numbers upto a limit(Using For Loop)

Solution : Without using function
Program/Source Code

#include <stdio.h>

int main()
{
    int n,i,z=0,limit;
    printf("Enter the limit ");
    scanf("%d",&limit);

    for(n=2;n<=limit;n++)
    {
        z=0;
        for(i=2;i<n;i++)
        {
            if(n%i==0)
            {
                z=1;
                break;
            }
        }
        if(z==0)
        printf("%d, ",n);
    }

    return 0;
}

Output:

Enter the limit 52
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47,

C program to print all prime numbers upto a limit(Using While Loop)

Solution : Without using function
Program/Source Code

#include <stdio.h>

int main()
{
    int n=2,i,z=0,limit;
    printf("Enter the limit ");
    scanf("%d",&limit);

    while(n<=limit)
    {
        z=0;
        i=2;
        while(i<n)
        {
            if(n%i==0)
            {
                z=1;
                break;
            }
            i++;
        }
        if(z==0)
        printf("%d, ",n);
        n++;
    }

    return 0;
}

Output:

Enter the limit 25
2, 3, 5, 7, 11, 13, 17, 19, 23,

C program to print all prime numbers upto a limit

Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
void check()
{
    int n,i,z=0,limit;
    printf("Enter the limit ");
    scanf("%d",&limit);

    for(n=2;n<=limit;n++)
    {
        z=0;
        for(i=2;i<n;i++)
        {
            if(n%i==0)
            {
                z=1;
                break;
            }
        }
        if(z==0)
        printf("%d, ",n);
    }

}

int main()
{
    check();
    return 0;
}

Output:

Enter the limit 15
2, 3, 5, 7, 11, 13,

C program to print all prime numbers upto a limit

Solution : Using function Passing Arguments
Program/Source Code

#include <stdio.h>
void check(int limit)
{
    int n,i,z=0;
    for(n=2;n<=limit;n++)
    {
        z=0;
        for(i=2;i<n;i++)
        {
            if(n%i==0)
            {
                z=1;
                break;
            }
        }
        if(z==0)
        printf("%d, ",n);
    }

}

int main()
{
    int limit;
    printf("Enter the limit ");
    scanf("%d",&limit);
    check(limit);
    return 0;
}

Output:

Enter the limit 35
2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31,

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