C Program to Check if the number is -ve or not

Solution with out using functions
Solution using functions without passing arguments
Solution using functions and by passing arguments

Solution : Without using function
Program/Source Code

#include <stdio.h>
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n<0)
         printf("Number is -ve");
     else
         printf("Number is not -ve");
 return 0;
 }

Output:

case 1:
Enter any no 26
Number is not -ve

case 2:
Enter any no -63
Number is -ve

Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
void check()
{
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n<0)
         printf("Number is -ve");
     else
         printf("Number is not -ve");
}
 int main()
 {
     check();
     return 0;
 }

Output:

case 1:
Enter any no 32
Number is not -ve

case 2:
Enter any no -87
Number is -ve

Solution : Using function Passing Arguments
Program/Source Code

#include <stdio.h>
void check(int n)
{
     if(n<0)
         printf("Number is -ve");
     else
         printf("Number is not -ve");
}
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     check(n);
     return 0;
 }

Output:

case 1:
Enter any no 34
Number is not -ve

case 2:
Enter any no -34
Number is -ve

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