C Program to check if the number is even or not

Solution with out using functions
Solution using functions without passing arguments
Solution using functions and by passing arguments



Solution : Without using function
Program/Source Code

#include <stdio.h>
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n%2==0)
         printf("Number is even");
     else
         printf("Number is not even");
 return 0;
 }

Output:

case 1:
Enter any no 36
Number is even

case 2:
Enter any no 23
Number is not even



Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
void check()
{
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n%2==0)
         printf("Number is even");
     else
         printf("Number is not even");
}
 int main()
 {
    check();
 return 0;
 }

Output:

case 1:
Enter any no 22
Number is even

case 2:
Enter any no 83
Number is not even



Solution : Using function Passing Arguments
Program/Source Code

#include <stdio.h>
void check(int n)
{
     if(n%2==0)
         printf("Number is even");
     else
         printf("Number is not even");
}
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
    check(n);
 return 0;
 }

Output:

case 1:
Enter any no 88
Number is even

case 2:
Enter any no 63
Number is not even

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