C Program to check if the number is odd or not

Solution with out using functions
Solution using functions without passing arguments
Solution using functions and by passing arguments



Solution : Without using function
Program/Source Code

#include <stdio.h>
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n%2==1) //or if(n%2!=0)
         printf("Number is Odd");
     else
         printf("Number is not Odd");
 return 0;
 }

Output:

case :1
Enter any no 57
Number is Odd

case :2
Enter any no 38
Number is not Odd



Solution : Using function Without Passing Arguments
Program/Source Code

#include <stdio.h>
void check()
{
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
     if(n%2==1) //or if(n%2!=0)
         printf("Number is Odd");
     else
         printf("Number is not Odd");
}
 int main()
 {
    check();
 return 0;
 }

Output:

case:1
Enter any no 25
Number is Odd

case:2
Enter any no 36
Number is not Odd



Solution : Using function Passing Arguments
Program/Source Code

#include <stdio.h>
void check(int n)
{
     if(n%2==1) //or if(n%2!=0)
         printf("Number is Odd");
     else
         printf("Number is not Odd");
}
 int main()
 {
     int n;
     printf("Enter any no ");
     scanf("%d",&n);
    check(n);
 return 0;
 }

Output:

case :1
Enter any no 49
Number is Odd

case :2
Enter any no 44
Number is not Odd

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