Question:5
Class Distance (km,m,cm,mm)
Declare a class named distance with attributes as km,m,cm and mm. Take input for two distances calculate and display their sum (Without using friend function).
Sol:
#include<iostream>
using namespace std;
class distance1
{
private:
int km,m,cm,mm;
public:
void read();
void show();
distance1 add(distance1 d);
};
void distance1::read()
{
cout<<"Enter km, m , cm and mm ";
cin>>km>>m>>cm>>mm;
}
void distance1::show()
{
cout<<km<<" km "<<m<<" m "<<cm<<" cm "<<mm<<" mm"<<endl;
}
distance1 distance1::add(distance1 d)
{
distance1 t;
t.km=km+d.km;
t.m=m+d.m;
t.cm=cm+d.cm;
t.mm=mm+d.mm;
if(t.mm>=10)
{
t.cm=t.cm+t.mm/10;
t.mm=t.mm%10;
}
if(t.cm>=100)
{
t.m=t.m+t.cm/100;
t.cm=t.cm%100;
}
if(t.m>=1000)
{
t.km=t.km+t.m/1000;
t.m=t.m%1000;
}
return(t);
}
int main()
{
distance1 e1,e2,e3;
e1.read(); e2.read();
e1.show(); e2.show();
e3=e1.add(e2);
e3.show();
return(0);
}
Output:
Enter km, m , cm and mm 2 50 45 5
Enter km, m , cm and mm 3 56 65 6
2 km 50 m 45 cm 5 mm
3 km 56 m 65 cm 6 mm
5 km 107 m 11 cm 1 mm
Question:6
Class time (hh, mm, ss)
Declare a class named time with attributes as hh,mm and ss. Take input for two time calculate and display their sum (Without using friend function).
Sol:
#include<iostream>
using namespace std;
class time1
{
private:
int hh,mm,ss;
public:
void read();
void show();
time1 add(time1 d);
};
void time1::read()
{
cout<<"Enter hh, mm and ss ";
cin>>hh>>mm>>ss;
}
void time1::show()
{
cout<<hh<<" hh "<<mm<<" mm "<<ss<<" ss "<<endl;
}
time1 time1::add(time1 d)
{
time1 t;
t.hh=hh+d.hh;
t.mm=mm+d.mm;
t.ss=ss+d.ss;
if(t.ss>=60)
{
t.mm=t.mm+t.ss/60;
t.ss=t.ss%60;
}
if(t.mm>=60)
{
t.hh=t.hh+t.mm/60;
t.mm=t.mm%60;
}
return(t);
}
int main()
{
time1 e1,e2,e3;
e1.read(); e2.read();
e1.show(); e2.show();
e3=e1.add(e2);
e3.show();
return(0);
}
Output:
Enter hh, mm and ss 2 50 20
Enter hh, mm and ss 4 30 45
2 hh 50 mm 20 ss
4 hh 30 mm 45 ss
7 hh 21 mm 5 ss




