C++ | Friend function 8

Adding two objects Without using the friend function

Note: Passing objects to function and function returning an object.

Question:1
Class Distance (feet and inches)
Declare a class named distance with attributes as feet and inches. Take the input for two distances, calculate and display their sum without using the friend function.
Sol:

#include<iostream>
using namespace std;
class distance1
{
	private:
		int feet,inches;
	public:
		void read();
		void show();
		distance1 add(distance1 d);
};
void distance1::read()
{
	cout<<"Enter feet and inches ";
	cin>>feet>>inches;
}
void distance1::show()
{
	cout<<feet<<" feet "<<inches<<" inches"<<endl;
}
distance1 distance1::add(distance1 d)
{
	distance1 t;
	t.feet=feet+d.feet;
	t.inches=inches+d.inches;
	if(t.inches>=12)
	{
		t.feet=t.feet+t.inches/12;
		t.inches=t.inches%12;
	}
	return(t);
}

int main()
{
	distance1 e1,e2,e3;
	e1.read(); e2.read();
	e1.show(); e2.show();
	e3=e1.add(e2);
	e3.show();
	return(0);
}

Output:

Enter feet and inches 4 10
Enter feet and inches 5 11
4 feet 10 inches
5 feet 11 inches
10 feet 9 inches

Question:2
class distance(km,m)
Declare a class named distance with attributes as km and m. Take input for two distances calculate and display their sum (Without using friend function).
Sol:

#include<iostream>
using namespace std;
class distance1
{
	private:
		int km,m;
	public:
		void read();
		void show();
		distance1 add(distance1 d);
};
void distance1::read()
{
	cout<<"Enter km and m ";
	cin>>km>>m;
}
void distance1::show()
{
	cout<<km<<" km "<<m<<" m"<<endl;
}
distance1 distance1::add(distance1 d)
{
	distance1 t;
	t.km=km+d.km;
	t.m=m+d.m;
	if(t.m>=1000)
	{
		t.km=t.km+t.m/1000;
		t.m=t.m%1000;
	}
	return(t);
}

int main()
{
	distance1 e1,e2,e3;
	e1.read(); e2.read();
	e1.show(); e2.show();
	e3=e1.add(e2);
	e3.show();
	return(0);
}

Output:

Enter km and m 2 500
Enter km and m 3 800
2 km 500 m
3 km 800 m
6 km 300 m

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